48-8x^2=16

Solution for 48-8x^2=16 equation:

48-8x^2=16

We move all terms to the left:

48-8x^2-(16)=0

We add all the numbers together, and all the variables

-8x^2+32=0

a = -8; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·(-8)·32
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*-8}=\frac{-32}{-16}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*-8}=\frac{32}{-16}
=-2
$